(Dividing 0 by a number)
When you divide 0 by a number, the quotient is always 0.
0 ÷ 4 = 0
When you divide a number by itself, the quotient is always 1.
7 ÷ 7 = 1
(Dividing by 4)
When dividing by 4, you can break the number in half and then half again.
To solve 24 ÷ 4, you can think of 24 ÷ 2 = 12 and then 12 ÷ 2 = 6
Look for the doubles multiplication facts in division problems. The quotient is always 2.
18÷ 9 = 2 14÷ 7 = 2
You can think about a division problem in terms of multiplication.
24 ÷ 6 6 x ? = 24 6 x 4 = 24
(Dividing by 1)
When you divide a number by 1, the quotient is that number. 6 ÷ 1 = 6
(Dividing by 2)
When dividing by 2, you break the number in half.
18 ÷ 2 Half of 18 is 9 because 9 x2 = 18
(Dividing by 8)
When dividing by 8, you can break the number in half, then half again and then half again.
To solve 64 ÷ 8, start with 64 ÷ 2 = 32, then 32 ÷ 2= 16, then 16 ÷ 2= 8
60 ÷ 5 Think 60 ÷ 10 = 6 ; half as many groups means twice as many in each group. So 60 ÷ 5 = 12
Materials: Flashcards or index cards with division facts written on them but no answers
Matches or pairs are made by matching quotients. (16 ÷ 4 and 8 ÷ 2 are a match) Players ask another for a quotient that would make a match with a card in his or her hand. Thus if the player has 12 ÷ 3 in his hand, he would ask another player for a 4. If that player has 24 ÷ 6 or any other card equaling 4, a match has been made, or “go fish”.
Materials: division flashcards/index cards with division facts written w/o answers
Place cards face down on a table or the floor. On each player’s turn, he or she turns over two cards and determines the quotient on each. If the quotients are equal, the player has made a match and keeps the cards. (Thus, 24 ÷ 8 and 6 ÷ 2 can be a match.) If the quotients are not equal, the two cards are turned back over and left in their place. The game ends when all matches are made. The winner is the player with the most matches.
Materials: 48 cards with one of the following written:
Lay cards face down. Each player draws seven cards, hiding cards from the other players. The remaining cards are removed except for one which remains face down. The first player chooses one he does not want and places it face down in front of the player to his left, and then picks up the extra card left on the table. Play rotates clockwise. Each player passes an unwanted card face down to the player on his/her left and then picks up the one given by the player on the right. The objective is to get seven cards with the same quotient. The game continues with players always placing one card on the table before picking up the next one.
Materials: Cards: 1, 3, 5, 7, 7, 9. Cards: 1, 2, 4, 6, 6, 8. List on lined paper 10-81.
Players take turns, rotating clockwise. To start, a player crosses out any unused number on the numbered list. All players use the same numbered list. He or she then choose one of the two sets of index cards and chooses one. Next, the player divides the number on the index card into the number he or she just crossed out and finds the remainder. The remainder for the division problem is the player’s score for that round. Players keep a cumulative sum of their scores from round to round.A player who notices another player make a mistake acquires that player’s score for the turn.The game ends when all of the numbers on the list have been crossed out. The player with the largest cumulative score at the end of the game wins. **To shorten: use numbers between 20 and 60.